Choose where you’d like to start

subYear()

Overview

The subYear() function takes dateTimeValue and numberOfYears as arguments. It returns the dateTimeValue after subtracting the specified number of years from it.

The date-time value will be returned in the format specified in Application Settings.

Return Type

  • Date-Time

Syntax

<variable> = <dateTimeValue>.subYear( <numberOfYears> );

(OR)

<variable> = subYear( <dateTimeValue>, <numberOfYears> );
ParameterDescriptionData type
<variable>Variable which will contain the returned date-time value.DATE-TIME
<dateTimeValue>

The date-time value from which the specified number of years will be subtracted.

The date-time value can be specified without a time value, in which case 00:00:00 will be taken as the default time value.

If the hour value is specified as 24 or more, the date-time value be reset to 00:00:00. If the minutes value is specified as 60 or more, the mm:ss value will be reset to 00:00, if the seconds value is specified as 60 or more, the ss value will be reset to 00.

A runtime error will be encountered if:

  • the hour value, or minute value, or second value, is specified in more than 2 digits.
  • the date value exceeds the number of days in that month.
  • an incorrect month value is specified.
  • the year value has more than 4 digits.

Refer this help document to learn about the supported date-time formats.

DATE-TIME
<numberOfYears>

The number of years to be subtracted from dateTimeValue.

A negative number will add the specified number of years to dateTimeValue.

NUMBER

Examples

currentDate = '01-Jan-2019';
newDate = currentDate.subYear(1);        // returns '01-Jan-2018 00:00:00'

Get Started Now

Execute